Forum Discussion
Related function search next matching value
Hi
I have to tables that are related. I want to do a search in the related table. Since the values in my facts table are averages, I don't have an exact match. So I want to search the first value in the related table that matches the average.
So in the example, I want to search the value in the related table that best matches my average cost
I did some searching but can't find the solution. Can someone have a look?
4 Replies
- amitchandak
Super User
jochendecraene , Create a new column in Fact
New column =
var _min = Maxx(filter(RelatedTable, RelatedTable[Item] = Fact[Item] && RelatedTable[Cost] <= Fact[Avg COst]), RelatedTable[Cost])
var _max = Maxx(filter(RelatedTable, RelatedTable[Item] = Fact[Item] && RelatedTable[Cost] > Fact[Avg COst]), RelatedTable[Cost])
return
if(_max -[Avg COst] > [Avg COst] - _min , _max, _min)You can use relatedtable or related, but that dependents on the relationship
refer 4 ways (related, relatedtable, lookupvalue, sumx/minx/maxx with filter) to copy data from one table to another
https://www.youtube.com/watch?v=Wu1mWxR23jU
https://www.youtube.com/watch?v=czNHt7UXIe8- jochendecraene
Helper V
thnx for the help.
now, when I create this column I get an a value > 117.000
Maybe I was not clear in my question, sorry.
What I need is the corresponding scale from the related table. So in this example the avg of 79.795,10 in my facts table needs to match the first higher value in my related table, wich is 80.316,37 and than give my the corresponding scale A1 19.
I have a many to one relations on the scale item.
- AnonymousNot applicable
Hi jochendecraene ,
I create a table as you mentioned.
Then I create two measures.
Average = AVERAGE('Table'[Count])Closest Match = VAR AverageCost = 'Table'[Average] VAR MinDifference = MINX ( RELATEDTABLE ( 'Table' ), ABS ( 'Table'[Count] - AverageCost ) ) VAR _Count = CALCULATE ( MIN ( 'Table'[Count] ), FILTER ( RELATEDTABLE ( 'Table' ), ABS ( 'Table'[Count] - AverageCost ) = MinDifference ) ) RETURN _CountFinally you will get what you want.
Best Regards
Yilong Zhou
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