Forum Discussion
Multiple field formatting values
- 6 years ago
Hi Anonymous , not sure how your data is organized, but you may take below steps for reference.
Sample data ‘Sales’
- If the large numbers and small numbers are in different fields:
1. Create a table ‘Years’ and enter the values 2013 and 2014.
2. Pick a slicer and add the Year column to its field.
3. Create a measure to display value in the matrix. You can modify the format here.
Display Sales = IF ( ISFILTERED ( Years[Year] ), SWITCH ( SELECTEDVALUE ( Years[Year] ), 2013, SUM ( Sales[Sales 2013] ), 2014, SUM ( Sales[Sales 2014] ) / 1000000 & "M" ), BLANK () )- If the large numbers and small numbers are in the same field:
1. Create a measure to display the value you need, you can modify the format here as you like.
Measure 2014 = VAR sumValue = SUM ( Sales[Sales 2014] ) RETURN IF ( sumValue > 1000000, sumValue / 1000000 & "M", sumValue )2. Add the measure in the matrix.
Best Regards,
Community Support Team _ Jing Zhang
If this post helps, please consider Accept it as the solution to help the other members find it more quickly.
Hi Anonymous , not sure how your data is organized, but you may take below steps for reference.
Sample data ‘Sales’
- If the large numbers and small numbers are in different fields:
1. Create a table ‘Years’ and enter the values 2013 and 2014.
2. Pick a slicer and add the Year column to its field.
3. Create a measure to display value in the matrix. You can modify the format here.
Display Sales =
IF (
ISFILTERED ( Years[Year] ),
SWITCH (
SELECTEDVALUE ( Years[Year] ),
2013, SUM ( Sales[Sales 2013] ),
2014, SUM ( Sales[Sales 2014] ) / 1000000 & "M"
),
BLANK ()
)
- If the large numbers and small numbers are in the same field:
1. Create a measure to display the value you need, you can modify the format here as you like.
Measure 2014 =
VAR sumValue = SUM ( Sales[Sales 2014] )
RETURN
IF ( sumValue > 1000000, sumValue / 1000000 & "M", sumValue )
2. Add the measure in the matrix.
Best Regards,
Community Support Team _ Jing Zhang
If this post helps, please consider Accept it as the solution to help the other members find it more quickly.
- Anonymous6 years agoNot applicable
Thank you so much for your help!!!!