Forum Discussion
make date from no
Hi all,
i have an issue:
how can i create date from these:
where 112018 = 1st jan 2018
6152018 = 15 jun 2018
11112018 = 11 nov 2017
thanks in advance!
Cosmin
This is not elegant and I'm hoping there is another solution that is...
Using:
date 112018 6152018 11112018 In the Query Editor ( Add Column > Custom Column) ,
YearNumTEXT = Text.End ( Number.ToText ( [date] ) , 4 )
DayNumTEXT = if Text.Length ( Number.ToText ( [date] ) ) = 6
then Text.Middle ( Number.ToText ( [date] ), 1, 1)
else if Text.Length ( Number.ToText ( [date] ) ) = 7
then Text.Middle ( Number.ToText ( [date] ), 1, 2)
else Text.Middle ( Number.ToText ( [date] ), 2, 2)MonthNumTEXT = if Text.Length ( Number.ToText ( [date] ) ) = 6
then Text.Start ( Number.ToText ( [date] ), 1)
else if Text.Length ( Number.ToText ( [date] ) ) = 7
then Text.Start ( Number.ToText ( [date] ), 1)
else Text.Start ( Number.ToText ( [date] ),2 )DateFromText = Date.FromText ( Text.Combine ( { [MonthNumTEXT], [DayNumTEXT], [YearNumTEXT] },"/") )That should allow you to format as Data Type Date.
6 Replies
This is not elegant and I'm hoping there is another solution that is...
Using:
date 112018 6152018 11112018 In the Query Editor ( Add Column > Custom Column) ,
YearNumTEXT = Text.End ( Number.ToText ( [date] ) , 4 )
DayNumTEXT = if Text.Length ( Number.ToText ( [date] ) ) = 6
then Text.Middle ( Number.ToText ( [date] ), 1, 1)
else if Text.Length ( Number.ToText ( [date] ) ) = 7
then Text.Middle ( Number.ToText ( [date] ), 1, 2)
else Text.Middle ( Number.ToText ( [date] ), 2, 2)MonthNumTEXT = if Text.Length ( Number.ToText ( [date] ) ) = 6
then Text.Start ( Number.ToText ( [date] ), 1)
else if Text.Length ( Number.ToText ( [date] ) ) = 7
then Text.Start ( Number.ToText ( [date] ), 1)
else Text.Start ( Number.ToText ( [date] ),2 )DateFromText = Date.FromText ( Text.Combine ( { [MonthNumTEXT], [DayNumTEXT], [YearNumTEXT] },"/") )That should allow you to format as Data Type Date.
Hi Chris,
very helpful and we're close, thanks a lot!
there are only 2 situation to solve:
1. when we have for example 12112018 (len=8)
2. 1112018 can be 11 jan and also 1 nov or 1212018 - can be 1 dec or 21 jan; in addition to this and i think very useful is that i obtained another column in which i had a date close to the date which we have to extract (not necessarily the same)
ex
1112018 1/13/2018
1212018 11/30/2018
Can you please digg on this please?
Thanks,
Cosmin
My demonstration should help you break the date into pieces so you can properly make into an actual date value.
If your data is in such a way that sometime 'month' comes before 'day' or vice versa that would be a very special case. How do you know that is the case by the way? I do not know of a way to find these ambigious cases.
Any chance you can get the source data cleaned up to be a standard 8 digit MMDDYYYY ? As it currently sits I don't see a way to parse the number into month, day and year.
For example: 1122018 - would this be 12 Jan 2018 or 2 Nov 2018 ?
Hi,
no but in addition i have a column with a date close to that:
1112018 1/13/2018
1212018 11/30/2018
Thanks,
Cosmin
