Forum Discussion
Looking for difference between two values by filters
Hi All,
I am looking for difference between two values like q2 and a3 cycles result should display the difference values based on the filter selected.
below the example: when i select the q2 and q3 it should display difference between those values at the end.
- Anonymous5 years ago
Hi Naveen_SV ,
I created a sample pbix file (see attachment) for you, please check whether that is what you want.
1. Create a calculated table: Table 2
Table 2 = UNION(VALUES('Table'[Cycle]),ROW("Cycle","XDifference"))2. Create measures to get the sum amount and difference
Measure = VAR _sAmountofQ1=CALCULATE(SUM('Table'[Amount]),FILTER('Table','Table'[ID] = MAX ( 'Table'[ID] ) &&'Table'[Cycle]="Q1")) VAR _sAmountofQ2=CALCULATE(SUM('Table'[Amount]),FILTER('Table','Table'[ID] = MAX ( 'Table'[ID] ) &&'Table'[Cycle]="Q2")) VAR _sAmountofQ3=CALCULATE(SUM('Table'[Amount]),FILTER('Table','Table'[ID] = MAX ( 'Table'[ID] ) &&'Table'[Cycle]="Q3")) VAR _sAmountofQ4=CALCULATE(SUM('Table'[Amount]),FILTER('Table','Table'[ID] = MAX ( 'Table'[ID] ) &&'Table'[Cycle]="Q4")) return SWITCH ( SELECTEDVALUE ( 'Table 2'[Cycle] ), "XDifference",_sAmountofQ4-_sAmountofQ3-_sAmountofQ2-_sAmountofQ1, CALCULATE ( SUM ( 'Table'[Amount] ), FILTER ( 'Table', 'Table'[ID] = MAX ( 'Table'[ID] )&&'Table'[Cycle]=MAX('Table 2'[Cycle]) ) ) )Difference = SUMX(VALUES('Table'[ID]),[Measure])3. Create a matrix visual (Rows: ID Column: field Cycle of Table 2 Values: [Difference] )
Best Regards
Rena
Community Support Team _ Rena Ruan
If this post helps, then please consider Accept it as the solution to help the other members find it more.
6 Replies
- AnonymousNot applicable
Hi Naveen_SV ,
What's your expected result? Whether the below table is what you want? If yes, you can refer the following threads to get it.
ID Q1 Q2 Q3 difference 23 245 245 24 45 27.89 -17.11 25 99.9 99.9 Subtract values in a measure for different categories
Dax - how to subtract one pivoted matrix column from another (power bi)
Best Regards
Rena
Community Support Team _ Rena Ruan
If this post helps, then please consider Accept it as the solution to help the other members find it more.- Naveen_SV
Helper IV
Anonymous Thanks for your reply, where here the scenrio is q1, q2, q3 is dynamic
- AnonymousNot applicable
Hi Naveen_SV ,
I created a sample pbix file (see attachment) for you, please check whether that is what you want.
1. Create a calculated table: Table 2
Table 2 = UNION(VALUES('Table'[Cycle]),ROW("Cycle","XDifference"))2. Create measures to get the sum amount and difference
Measure = VAR _sAmountofQ1=CALCULATE(SUM('Table'[Amount]),FILTER('Table','Table'[ID] = MAX ( 'Table'[ID] ) &&'Table'[Cycle]="Q1")) VAR _sAmountofQ2=CALCULATE(SUM('Table'[Amount]),FILTER('Table','Table'[ID] = MAX ( 'Table'[ID] ) &&'Table'[Cycle]="Q2")) VAR _sAmountofQ3=CALCULATE(SUM('Table'[Amount]),FILTER('Table','Table'[ID] = MAX ( 'Table'[ID] ) &&'Table'[Cycle]="Q3")) VAR _sAmountofQ4=CALCULATE(SUM('Table'[Amount]),FILTER('Table','Table'[ID] = MAX ( 'Table'[ID] ) &&'Table'[Cycle]="Q4")) return SWITCH ( SELECTEDVALUE ( 'Table 2'[Cycle] ), "XDifference",_sAmountofQ4-_sAmountofQ3-_sAmountofQ2-_sAmountofQ1, CALCULATE ( SUM ( 'Table'[Amount] ), FILTER ( 'Table', 'Table'[ID] = MAX ( 'Table'[ID] )&&'Table'[Cycle]=MAX('Table 2'[Cycle]) ) ) )Difference = SUMX(VALUES('Table'[ID]),[Measure])3. Create a matrix visual (Rows: ID Column: field Cycle of Table 2 Values: [Difference] )
Best Regards
Rena
Community Support Team _ Rena Ruan
If this post helps, then please consider Accept it as the solution to help the other members find it more.
- sarath_chandra
Helper III
Anonymous Naveen_SV please help me to give solution for my above query. Highly appreciative