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surajde's avatar
surajde
Helper I
3 years ago
Solved

Last Modified Time

HI All, 

 

Need your help with BI Formula for below dummy data. 
In excel it was much easy. Need to push this to PowerBI. Please help with below scenario to replicate this in PowerBi

 

if you copy this to Excel use below formula in Current Group Time Column: 

=IF(A2<>A1, E2, IF(B2<>B1, E2, F1))

 

Expected result should be as per Current Group Time. 

 

Request IDGroup NameAnalystRequest Created onRequest Modified on Current Group Time
K1122334MOD Tier 1-5/1/23 10:32 AM5/1/23 10:32 AM5/1/23 10:32 AM
K1122334MOB IT PPET-5/1/23 10:32 AM5/1/23 10:48 AM5/1/23 10:48 AM
K1122334IT_Q2A_E2E-5/1/23 10:32 AM5/1/23 12:01 PM5/1/23 12:01 PM
K1122334IT_Q2A_E2EShawn Trieloff5/1/23 10:32 AM5/1/23 12:36 PM5/1/23 12:01 PM
C2244666MOD Tier 1-5/1/23 10:55 AM5/1/23 10:55 AM5/1/23 10:55 AM
C2244666MOD Tier 1-5/1/23 10:55 AM5/1/23 10:57 AM5/1/23 10:55 AM
C2244666MOD Tier 1Neelam Seth5/1/23 10:55 AM5/1/23 11:11 AM5/1/23 10:55 AM
C2244666MOD Tier 1Neelam Seth5/1/23 10:55 AM5/1/23 11:50 AM5/1/23 10:55 AM
D6677888MOD Tier 1-5/1/23 1:00 PM5/1/23 1:00 PM5/1/23 1:00 PM
D6677888MOD Tier 1Anand Mane5/1/23 1:00 PM5/1/23 1:35 PM5/1/23 1:00 PM
D6677888MOD Tier 1Neelam Seth5/1/23 1:00 PM5/1/23 4:54 PM5/1/23 1:00 PM
D6677888MOD Tier 1Neelam Seth5/1/23 1:00 PM5/1/23 4:55 PM5/1/23 1:00 PM
D6677888MOD Tier 1-5/1/23 1:00 PM5/5/23 12:45 PM5/1/23 1:00 PM
D6677888BMG Management-5/1/23 1:00 PM5/5/23 12:58 PM5/5/23 12:58 PM
D6677888BMG ManagementCourtney Morgan5/1/23 1:00 PM5/10/23 4:37 PM5/5/23 12:58 PM
D6677888MOD Tier 1-5/1/23 1:00 PM5/16/23 1:59 PM5/16/23 1:59 PM
D6677888MOD Tier 1Anand Mane5/1/23 1:00 PM5/16/23 2:35 PM5/16/23 1:59 PM
D6677888MOD Tier 1Abhishek Mishra5/1/23 1:00 PM5/16/23 4:00 PM5/16/23 1:59 PM
D6677888MOD Tier 1Bheemsen Dasnurkar5/1/23 1:00 PM5/17/23 12:59 AM5/16/23 1:59 PM
D6677888MOD Tier 1Bheemsen Dasnurkar5/1/23 1:00 PM5/17/23 1:05 AM5/16/23 1:59 PM
J4357593MOD Tier 1-5/2/23 1:52 AM5/2/23 1:52 AM5/2/23 1:52 AM
J4357593MOD Tier 1Bheemsen Dasnurkar5/2/23 1:52 AM5/2/23 1:56 AM5/2/23 1:52 AM
J4357593FI Quality-5/2/23 1:52 AM5/2/23 8:51 AM5/2/23 8:51 AM
J4357593FI QualityRahul Pawar5/2/23 1:52 AM7/28/23 2:03 PM5/2/23 8:51 AM
  • Anonymous's avatar
    Anonymous
    3 years ago

    Hi surajde ,

     

    According to your description, here are my steps you can follow as a solution.

    (1) My test data is the same as yours.

    (2)Click on "transform data" to enter the power query and add index a column.

    (3) We can create calculated columns.

    Column = MAXX(FILTER('Table',[Request ID]=EARLIER('Table'[Request ID])&&[Index]=EARLIER('Table'[Index])-1),[Group Name])
    Column 2 = IF(OR([Column]=BLANK(),[Group Name]<>[Column]),[Request Modified on ])
    Column 3 = var a=MAXX(FILTER('Table',[Request ID]=EARLIER('Table'[Request ID])&&[Group Name]=EARLIER('Table'[Group Name])&&[Index]<EARLIER('Table'[Index])&&[Column 2]<>BLANK()),[Index])
    return IF([Column 2]<>BLANK(),[Column 2],IF([Group Name]=[Column],LOOKUPVALUE('Table'[Column 2],'Table'[Index],a)))

    (4) Then the result is as follows.

    Best Regards,

    Neeko Tang

    If this post  helps, then please consider Accept it as the solution  to help the other members find it more quickly. 

1 Reply

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi surajde ,

     

    According to your description, here are my steps you can follow as a solution.

    (1) My test data is the same as yours.

    (2)Click on "transform data" to enter the power query and add index a column.

    (3) We can create calculated columns.

    Column = MAXX(FILTER('Table',[Request ID]=EARLIER('Table'[Request ID])&&[Index]=EARLIER('Table'[Index])-1),[Group Name])
    Column 2 = IF(OR([Column]=BLANK(),[Group Name]<>[Column]),[Request Modified on ])
    Column 3 = var a=MAXX(FILTER('Table',[Request ID]=EARLIER('Table'[Request ID])&&[Group Name]=EARLIER('Table'[Group Name])&&[Index]<EARLIER('Table'[Index])&&[Column 2]<>BLANK()),[Index])
    return IF([Column 2]<>BLANK(),[Column 2],IF([Group Name]=[Column],LOOKUPVALUE('Table'[Column 2],'Table'[Index],a)))

    (4) Then the result is as follows.

    Best Regards,

    Neeko Tang

    If this post  helps, then please consider Accept it as the solution  to help the other members find it more quickly.