Forum Discussion

music43's avatar
music43
Advocate II
3 years ago
Solved

Hide Rows in Table/Matrix

Hi

 

I have a table/matrix with a couple of dimensions and ten measures. Two of the measures will always return a value (M7 & M8).

 

Is there a way to only show the rows where there is a value in one of the other 8 measures (M1 thru M6)?

In this example I would like to hide rows D and G. In my real world caseI have hundreds or rows I need hidden.

 

Thanks in advance.

 

Oli

 

 

 

 

  • Anonymous's avatar
    Anonymous
    3 years ago

    Hi music43 ,

     

    I suggest you to try to create a measure to filter your visual.

    Filter = 
    VAR _Condition = ISBLANK([M1])&&ISBLANK([M2])&&ISBLANK([M3])&&ISBLANK([M4])&&ISBLANK([M5])&&ISBLANK([M6])
    RETURN
    IF(_Condition,0,1)

    Add this measure into visual level filter and set this measure to show items when value = 1.

     

    Best Regards,
    Rico Zhou

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

3 Replies

  • Hi music43 

    Rows cannot be hidden in the visualization, but they can be filtered.
    Create a flag measure that checks if your measures return blank values.
    According to this measure, filter the table.

    If this post helps, then please consider Accepting it as the solution to help the other members find it more quickly

  • Hi,

    You can hide rows in a table/matrix by using the exclude option by right-clicking on the row you want to hide or can filter it.

     

    Thank You

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi music43 ,

     

    I suggest you to try to create a measure to filter your visual.

    Filter = 
    VAR _Condition = ISBLANK([M1])&&ISBLANK([M2])&&ISBLANK([M3])&&ISBLANK([M4])&&ISBLANK([M5])&&ISBLANK([M6])
    RETURN
    IF(_Condition,0,1)

    Add this measure into visual level filter and set this measure to show items when value = 1.

     

    Best Regards,
    Rico Zhou

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.