Forum Discussion
Amymai
7 years agoFrequent Visitor
Find Consecutive Rows
Hi everyone,
I want to find 2 and 3 consecutive rows where Index equals 1 and show the results as below.
Can you please help me. I'd like to use DAX, not power query as I can't go back to query at this step.
Thanks so much!
| Index | 2 consecutive rows (result) | 3 consecutive rows (result) |
| 1 | 1 | 0 |
| 1 | 1 | 0 |
| 0 | 0 | 0 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 0 | 0 | 0 |
| 1 | 0 | 0 |
| 0 | 0 | 0 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
v-chuncz-msft Thank you so much!!! It works.
2 Replies
- v-chuncz-msft
Community Support
You may add an index column in Query Editor and use DAX below to add a calculated column.
Column = VAR c = 2 RETURN IF ( Table1[Index] = 0 || VAR i = Table1[Index.1] VAR p = MAXX ( FILTER ( Table1, Table1[Index.1] < i && Table1[Index] = 0 ), Table1[Index.1] ) VAR n = MINX ( FILTER ( Table1, Table1[Index.1] > i && Table1[Index] = 0 ), Table1[Index.1] ) RETURN IF ( ISBLANK ( n ), MAX ( Table1[Index.1] ) + 1, n ) - IF ( ISBLANK ( p ), MIN ( Table1[Index.1] ) - 1, p ) - 1 < c, 0, 1 )- AmymaiFrequent Visitor
v-chuncz-msft Thank you so much!!! It works.