Forum Discussion
Double distinct count
Hello, everyone 🙂
My table follows this structure:
| COD | CV |
| 111 | 11.1 |
| 111 | 15.2 |
| 111 | 16.2 |
| 222 | 11.2 |
| 222 | 16.2 |
| 333 | 11.1 |
| 333 | 15.2 |
| 333 | 15.2 |
I would like to create a measure that distinct counts all types of CVs that are neither 11.1 nor 11.2, for each distinct COD.
So, in the example table above, the count should be:
COD 111 = 2 (CV 15.2 and CV 16.2)
COD 222 = 1 (CV 16.2)
COD 333 = 1 (CV 15.2)
So, the measure should bring me the value 4 (2 +1 + 1).
Can someone help me?
@req7 Try this measure. I uploaded a PBIX file below.
Measure = COUNTROWS( SUMMARIZE( FILTER( 'Table (2)', [CV ] <> 11.1 && [CV ]<>11.2 ), [COD ],[CV ] ) )
3 Replies
Anonymous , Try like
sumx(Values(Table[COD ]),calculate( distinctCOUNT(Table[CV]) filter(Table, not(Table[CV] in {11.1 , 11.2}))))
sumx(Values(Table[COD ]),calculate( distinctCOUNT(Table[CV]) filter(Table, not(Table[CV] in {"11.1" , "11.2"}))))@req7 Try this measure. I uploaded a PBIX file below.
Measure = COUNTROWS( SUMMARIZE( FILTER( 'Table (2)', [CV ] <> 11.1 && [CV ]<>11.2 ), [COD ],[CV ] ) )Hi,
This measure works
=SUMX(SUMMARIZE(VALUES(Data[COD]),Data[COD],"ABCD",CALCULATE(DISTINCTCOUNT(Data[CV]),Data[CV]<>11.1,Data[CV]<>11.2)),[ABCD])
Hope this helps.
