Forum Discussion
Difference in time between records in the same column
- 9 years ago
Perhaps use a measure that calculates the difference between the MIN and MAX of the column?
- 9 years ago
Anonymous,
Through slicing I want to know what the time is between for example A and B which would give 00:10:00 in this example.
So you will select two items in your slicer? If that is the case, you can use the measure below.
Difference = MAX(Table1[TimePoint])-MIN(Table1[TimePoint])Regards,
Charlie Liao
Anonymous,
Through slicing I want to know what the time is between for example A and B which would give 00:10:00 in this example.
So you will select two items in your slicer? If that is the case, you can use the measure below.
Difference = MAX(Table1[TimePoint])-MIN(Table1[TimePoint])
Regards,
Charlie Liao
- Anonymous9 years agoNot applicable
Hi all,
First of all thanks for taking time to help me.
And yes this worked the same for me as in the example v-caliao-msft recreated. The next step in my formula would be to calculate a distance by "TimeDifference" * "speed". Although I am not sure how to approach this problem since I don't know how to make the multiply understand that I want "TimeDifference" multiplied by the speed the object had between point A and B or A and C for example. I was wondering if any of you had an idea on how to approach this problem.
Regards,
L. Meijdam