Forum Discussion
DAX - Calculating and Comparing the Difference Between Two Dates, Count Records Based on Results
Hi!
I am still learning the ropes for DAX and need some help. I have used Tableau in the past and know how to do it using their calculated fields, but I can't seem to do it in Power BI.
I am trying to create a measure that does the following: DATEDIFF between two date fields in the same table, counting the number of days between them. Then, count the record if the number of days between the two dates are greater than 7.
This is how I know to do it in Tableau:
Measure 1:
IF (
DATEDIFF('day', [date1], [date2] )
) > 7 then [recordid]
END
Then I could just count this measure.
This is what I have in Power BI (I know this isn't working correctly):
Hi, Anonymous
You can try the following methods.
Column:
Column = CALCULATE(COUNT(table_A[recordid]),FILTER(table_A,DATEDIFF([date1],[date2],DAY) > 7))Measure:
Difference = DATEDIFF( MAX(table_A[date1]),MAX(table_A[date2]),DAY)Open More Than 7 Days = CALCULATE(COUNT(table_A[recordid]),FILTER(ALL(table_A),[Difference]>7))Is this the result you expect?
Best Regards,
Community Support Team _Charlotte
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 Replies
- amitchandak
Super User
Anonymous , Create a new column
IF( DATEDIFF(table_A[date1],table_A[date2],DAY) > 7, table_A[recordid], blank() )
or a measure
sumx(table_A, IF( DATEDIFF(table_A[date1],table_A[date2],DAY) > 7, table_A[recordid], blank() ))
- v-zhangti
Community Support
Hi, Anonymous
You can try the following methods.
Column:
Column = CALCULATE(COUNT(table_A[recordid]),FILTER(table_A,DATEDIFF([date1],[date2],DAY) > 7))Measure:
Difference = DATEDIFF( MAX(table_A[date1]),MAX(table_A[date2]),DAY)Open More Than 7 Days = CALCULATE(COUNT(table_A[recordid]),FILTER(ALL(table_A),[Difference]>7))Is this the result you expect?
Best Regards,
Community Support Team _Charlotte
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.