Forum Discussion

Anonymous's avatar
Anonymous
Not applicable
3 years ago
Solved

Week sort

Hi all!   please help me with the following,   I have a column Week , which contains begging and end of week, I was planning to sort it by date, but power bi returns an error "Sort by another co...
DAX
Need Help
  • tamerj1's avatar
    tamerj1
    3 years ago

    Anonymous 
    You are digging in the wrong location. When to stop repeating? That brings you back to the original problem of ranking using the correct granularity. This is an infinite loop and will lead to nowhere.

    The issue is that your business logic wasn't clarified so I had to guess. You can achieve this using

    day_rank =
RANKX (
    'Calendar',
    'Calendar'[Date] - WEEKDAY ( 'Calendar'[Date], 2 ),
    ASC,
    DENSE
)

     

tamerj1's avatar
tamerj1
Community Champion
3 years ago

Anonymous 
These are in two different years. The week sort says one is the last week of 2018 and the other is the first week 2019.  You shuld fix the week sort column, either to consider these 7 days as the last week of 2018 or to consider then as the first week of 2019. I mean week and week sort must be alligned.

Anonymous's avatar
Anonymous
Not applicable
3 years ago

tamerj1 ,

 

I see, but how? 🙂

 

Formula in Week column is:

Week =
FORMAT(
    'Calendar'[Date] - WEEKDAY('Calendar'[Date],2)+1,
    "dd-MMM")
    &" - "&
FORMAT(
    'Calendar'[Date] - WEEKDAY('Calendar'[Date],2)+7,
    "dd-MMM")
and it's automatically catches those days, it there a way to limit which days fall into which week?

 

  • tamerj1's avatar
    tamerj1
    Community Champion
    3 years ago

    Anonymous 
    Please try

    Week =
FORMAT ( 'Calendar'[Date] - WEEKDAY ( 'Calendar'[Date], 2 ) + 1, "dd-MMM" ) & " - "
    & FORMAT (
        MIN (
            'Calendar'[Date] - WEEKDAY ( 'Calendar'[Date], 2 ) + 7,
            ENDOFYEAR ( 'Calendar'[Date] )
        ),
        "dd-MMM"
    )
    • Anonymous's avatar
      Anonymous
      Not applicable
      3 years ago

      your solution works tamerj1  and will accept it,
      but it creates this short week containing only one day, and I know my colleagues will ask why ğŸ˜…

       

       

      do you maybe know if it's possible to somehow repeat a value from row above on condition from other column,
      like here, I did rankx of Date column

      day_rank =
      RANKX(
          'Calendar',
          'Calendar'[Date],,ASC)
      and maybe it's possible to write a logical function ( using REPT, IF, EARLIER) that will check if next row in Week column is equial to previous one, if true, then repeat Day_rank row, if not then Day_rank?
       

      thanks for all your help!

      • tamerj1's avatar
        tamerj1
        Community Champion
        3 years ago

        Anonymous 
        You are digging in the wrong location. When to stop repeating? That brings you back to the original problem of ranking using the correct granularity. This is an infinite loop and will lead to nowhere.

        The issue is that your business logic wasn't clarified so I had to guess. You can achieve this using

        day_rank =
RANKX (
    'Calendar',
    'Calendar'[Date] - WEEKDAY ( 'Calendar'[Date], 2 ),
    ASC,
    DENSE
)