Forum Discussion
bestevez
Helper I
Helper IRANKX AND ORDER
Hello,
I have a question I'd like to raise so that I can resolve it. As you can see in the table I would like to add a column (RANKX ORDER LY) where appears the ranking of last year's products that had the same order as this year's products.
The RANKX and RANKX LY columns work perfectly.
| YEAR | PRODUCT | QTY | RANKX | ||
| 2018 | PEPSI | 50 | 1 | ||
| 2018 | COCA COLA | 45 | 2 | ||
| 2018 | ORANGE | 30 | 3 | ||
| 2018 | PEPSI MAX | 25 | 4 | ||
| 2018 | COCA COLA ZERO | 10 | 5 | ||
| RANKX | RANKX LY | RANKX ORDER LY | |||
| 2019 | COCA COLA | 55 | 1 | 2 | PEPSI |
| 2019 | PEPSI MAX | 40 | 2 | 4 | COCA COLA |
| 2019 | PEPSI | 35 | 3 | 1 | ORANGE |
| 2019 | COCA COLA ZERO | 30 | 4 | 5 | PEPSI MAX |
| 2019 | ORANGE | 28 | 5 | 3 | COCA COLA ZERO |
Thanks
3 Replies
Hello.
I do have a suggestion, albeit not a particularly elogant solution...
To achieve the table shown I would suggest first create the RANKX formula in your data table:
RANKX =RANKX(FILTER(data_table,data_table[YEAR]=EARLIER(data_table[YEAR])),data_table[QTY])You can then use this to create a calculated table as follows:
RankLY = SUMMARIZECOLUMNS(data_table[YEAR],data_table[PRODUCT],data_table[QTY],data_table[RANKX])Back in your main data table you can then create two calculated columns which call back the desired values:RANKX LY = LOOKUPVALUE(RankLY[RANKX],RankLY[YEAR],data_table[YEAR]-1,RankLY[PRODUCT],data_table[PRODUCT])And....RANKX ORDER LY = LOOKUPVALUE(RankLY[PRODUCT],RankLY[YEAR],data_table[YEAR]-1,RankLY[RANKX],data_table[RANKX])Hope this maybe of some use to you 😊
bestevezThanks i try it.
MartynRamsdenSolution Sage
Hi bestevez
Not sure if I'm over simplifying things but I think you could use the LOOKUPVALUE function as follows.
RANKX ORDER LY = LOOKUPVALUE ( 'Table'[PRODUCT], 'Table'[RANKX LY], 'Table'[RANKX] )Best regards,
Martyn
