Forum Discussion
New Customer column
- Anonymous3 years ago
Hi mmh
You can try the following code:
New Customer = var _filter=FILTER('Table',[Customer_id]=EARLIER('Table'[Customer_id])) var _indate=MINX(_filter,[valid_from]) var _end=MAXX(FILTER(_filter,[valid_from]=_indate),[Valid_to]) return IF([valid_from]>=_indate&&[Valid_to]<=_end,"Yes","No")Output
Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi mmh
You can refer to the following example:
New Customer = IF(MONTH('Table'[valid_from])=1&&DAY([valid_from])=1,"Yes","No")
Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- mmh3 years ago
Helper I
HI Yolo,
Thanks! But its not correct. Actually here some new customer having two records as like
Intials date n approved date , so it would be identified as new customer in both recordsCustomer_id valid_from Valid_to New Customer 202 1-1-1800 1-1-3000 Yes 202 1-1-2023 1-2-2024 Yes Otherside some customer having record as like
Customer_id validFrom Validto New Customer ? 101 1-1-2020 1-2-2021 Yes 101 2-1-2021 3-1-2022 NO - mmh3 years ago
Helper I
HI Yolo,
Thanks! But its not correct. Actually here some new customer having two records as like
Intials date n approved date , so it would be identified as new customer in both recordsCustomer_id valid_from Valid_to New Customer 202 1-1-1800 1-1-3000 Yes 202 1-1-2023 1-2-2024 Yes Otherside some customer having record as like
Customer_id validFrom Validto New Customer ? 101 1-1-2020 1-2-2021 Yes 101 2-1-2021 3-1-2022 NO Thank You!
- Anonymous3 years agoNot applicable
Hi mmh
You can try the following code:
New Customer = var _filter=FILTER('Table',[Customer_id]=EARLIER('Table'[Customer_id])) var _indate=MINX(_filter,[valid_from]) var _end=MAXX(FILTER(_filter,[valid_from]=_indate),[Valid_to]) return IF([valid_from]>=_indate&&[Valid_to]<=_end,"Yes","No")Output
Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.