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Anonymous's avatar
Anonymous
Not applicable
7 years ago

Need help with a multicase SWITCH statement

The logic I am attempting to follow is:

  •  

 

If column 1 equals True then "Some Designation 1"

If column 2 equals True then "Some Designation 2"

If Column 3 equals "Some Value1" AND Column 4 equals 1 or 2 or 3 or 4 or 5 Then "Some Designation 3"

If Column 3 equals "Some Value2" AND Column 4 equals 1 or 2 or 3 or 4 or 5 Then "Some Designation 3"

Else "Undefined"

 

I cannot seem to get my SWITCH Correct:

Designation = SWITCH(
    TRUE(),
    'Table'[column1] = True, "Some Designation 1",
    'Table1'[Column2 = True, "Some Designation 2",
    'Table1'[column3] = "Some Value 1" 
    && 'Table1'[Column 4] = "1"||
        'Table1'[Column 4] = "2" || 
        'Table1'[Column 4] = "3" || 
        'Table1'[Column 4] = "4" || 
        'Table1'[Column 4] = "5" || 
        'Table1'[Column 4] = "6" || 
        'Table1'[Column 4] = "7" || 
        'Table1'[Column 4] = "8", 
        "Some Designation 3",
        'Table1'[column3] = "Some Value 2" 
    && 'Table1'[Column 4] = "1"||
        'Table1'[Column 4] = "2" || 
        'Table1'[Column 4] = "3" || 
        'Table1'[Column 4] = "4" || 
        'Table1'[Column 4] = "5" || 
        'Table1'[Column 4] = "6" || 
        'Table1'[Column 4] = "7" || 
        'Table1'[Column 4] = "8", 
        "Some Designation 3", 
        "Undefined")

1 Reply

  • v-anabat's avatar
    v-anabat
    Icon for Microsoft Employee rankMicrosoft Employee
    7 years ago

    Hi, 

     

    please check if the below formula works 

    Result = SWITCH(TRUE(),
                    'Table'[Column 1] = TRUE(), "Some Designation 1",
                    'Table'[Column 2] = TRUE(), "Some Designation 2",
                    'Table'[Column 3] IN {"1","2"} &&  'Table'[Column 4] IN {"1","2","3","4","5"}, "Some Designation 3",
                    "Undefined"
    )
    Based on your explination, I assumed data set/result as present in below sceenshot.
    If it is different provide the same dataset