Forum Discussion
How can i subtract a value by date ? [Solved]
I have a table that looks like this:
what i need to do to add a column that subtract a certain amount (this certain amount will be a measure) considering the date ?
So i have something like this:
Hi cccarv82
Here is the sample file with the solution https://we.tl/t-eHYz5Ypz3FI hope this is what you're looking for
Actual Value = VAR Current_Value = Table_1[value] VAR Current_Date = Table_1[date_day_by_day] VAR CurrentItem_Table = CALCULATETABLE ( Table_1, ALLEXCEPT ( Table_1, Table_1[Name] ) ) VAR First_Date = MINX ( CurrentItem_Table, Table_1[date_day_by_day] ) VAR Last_Date = MAXX ( CurrentItem_Table, Table_1[date_day_by_day] ) VAR NumberOfDays = DATEDIFF ( First_Date, Current_Date, DAY ) VAR TotalNumberOfDays = DATEDIFF ( First_Date, Last_Date, DAY ) VAR DailyValue = DIVIDE ( Current_Value, TotalNumberOfDays ) RETURN Current_Value - DailyValue * NumberOfDays
8 Replies
- tamerj1
Community Champion
Hi cccarv82
Here is the sample file with the solution https://we.tl/t-eHYz5Ypz3FI hope this is what you're looking for
Actual Value = VAR Current_Value = Table_1[value] VAR Current_Date = Table_1[date_day_by_day] VAR CurrentItem_Table = CALCULATETABLE ( Table_1, ALLEXCEPT ( Table_1, Table_1[Name] ) ) VAR First_Date = MINX ( CurrentItem_Table, Table_1[date_day_by_day] ) VAR Last_Date = MAXX ( CurrentItem_Table, Table_1[date_day_by_day] ) VAR NumberOfDays = DATEDIFF ( First_Date, Current_Date, DAY ) VAR TotalNumberOfDays = DATEDIFF ( First_Date, Last_Date, DAY ) VAR DailyValue = DIVIDE ( Current_Value, TotalNumberOfDays ) RETURN Current_Value - DailyValue * NumberOfDays- cccarv82Frequent Visitor
- amitchandak
Super User
cccarv82 , you can simply subtract a number
new column
new date = [Date] -[Number]
or
new date = [Date] -10
- cccarv82Frequent Visitor
hi amitchandak !
This way i will subtract the date. I need something like
[Number] - [Measure]But this doesnt work aswell because i will have the same result for all rows. I need to have a new result per row, like this:
the [number_by_date] is my new column where i have the result of the subtract but i i just use [number] - [measure] i will have the wrong result.
- cccarv82Frequent Visitor
Hi tamerj1 !!
First i have this column:
For each item i have a value, ok... then i expanded my table to be daily detailed and reach this:
Now i have the same value for each row but i want to add a column to show the new value where each day i subtract a measured value for each item so i can have Item 1 from 10 to 0 from 01/04/2022 to 14/04/2022 (in this example) and for Item 2 i will have from 10 to 0 from 15/04/2022 to 26/04/2022.
Here is the file:
- tamerj1
Community Champion
I'll work on it and get back to you by tomorrow morning. Thank you