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Anonymous's avatar
Anonymous
Not applicable
2 years ago
Solved

Help splitting this column

 

I need to split this by dd/mm/yyyy (UK date format).

I'm in need of an DAX formula that'll extract the date portion (02022024) of the Source Name column and then return the result in the above manner. 

If someone can guide me in this, it'll be wonderful. I'm very raw with DAX. 

  • govindarajan_d's avatar
    govindarajan_d
    2 years ago

    Hi Anonymous,

     

    Can you please try this:

     

     

    Date =
VAR DatePosition =
    LEN ( Files[FileName] ) - LEN ( "ddmmyyyy" )
        - LEN ( ".xlsx" ) + 1
VAR DateString =
    MID ( Files[FileName], DatePosition, 8 )
RETURN
    FORMAT (
        DATE ( RIGHT ( DateString, 4 ), MID ( DateString, 3, 2 ), LEFT ( DateString, 2 ) ),
        "dd/mm/yyyy"
    )

     

     

     

     

    Upvote and accept as a solution if it helps!

     

4 Replies

  • govindarajan_d's avatar
    govindarajan_d
    Super User
    2 years ago

    Hi Anonymous,

     

    Can you please try this:

     

     

    Date =
VAR DatePosition =
    LEN ( Files[FileName] ) - LEN ( "ddmmyyyy" )
        - LEN ( ".xlsx" ) + 1
VAR DateString =
    MID ( Files[FileName], DatePosition, 8 )
RETURN
    FORMAT (
        DATE ( RIGHT ( DateString, 4 ), MID ( DateString, 3, 2 ), LEFT ( DateString, 2 ) ),
        "dd/mm/yyyy"
    )

     

     

     

     

    Upvote and accept as a solution if it helps!

     

      • Anonymous's avatar
        Anonymous
        Not applicable
        2 years ago

        Hi, sorry for the very late response. I'm going to check now and get back to you.