Forum Discussion
Find the nearest value within a month
Hello community!
Is anyone familiar with writing the Dax Programming to find the nearest (closest ) value in the table?
For example, My table is like this:
And I want to find the nearest Model built time value with 1 month average built time (in this case, today date is 2022/11/16 so
(213 + 444 + 532 + 111 / 4 ) = 325 )
so the nearest value of 325 in this table should be 213 (A125) not 345 (A124) as that model not in a past month from current date.
Therefore, how do i return 213 using the dax programming?
Thank you so much for your help!
Hi, heejinyune
You can try the following methods.
Column:Month = MONTH([Model built Date])Measure:
Nearest Average = CALCULATE(AVERAGE('Table'[Model built time]),FILTER(ALL('Table'),[Month]=MONTH(TODAY())))Difference = ABS(SUM('Table'[Model built time])-[Nearest Average])Nearest Value = Var _mindiff=MINX(FILTER(ALL('Table'),[Month]=MONTH(TODAY())),[Difference]) Return IF([Difference]=_mindiff,SUM('Table'[Model built time]))Is this the result you expect?
Best Regards,
Community Support Team _Charlotte
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
1 Reply
v-zhangtiCommunity Support
Hi, heejinyune
You can try the following methods.
Column:Month = MONTH([Model built Date])Measure:
Nearest Average = CALCULATE(AVERAGE('Table'[Model built time]),FILTER(ALL('Table'),[Month]=MONTH(TODAY())))Difference = ABS(SUM('Table'[Model built time])-[Nearest Average])Nearest Value = Var _mindiff=MINX(FILTER(ALL('Table'),[Month]=MONTH(TODAY())),[Difference]) Return IF([Difference]=_mindiff,SUM('Table'[Model built time]))Is this the result you expect?
Best Regards,
Community Support Team _Charlotte
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.