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Destrogiro's avatar
Destrogiro
Regular Visitor
6 years ago
Solved

EARLIER Function

Hi, I'm new to Power BI and I'm having trouble with EARLIER function. Basically what I need is:   ValorTotal = SWITCH(TCBLBI_Peso_Empresas_Tradadas[OrdemGrupo];                     2; EARLIER([Va...
  • AlB's avatar
    AlB
    6 years ago

    Since the introduction of VAR, there's no actual need for EARLIER any longer.  So you might want to do it in a different way, perhaps easier to follow conceptually, and forget about EARLIER altogether (which is actually recommended nowadays):

    Value2 =
SWITCH (
    TRUE (),
    Table1[GroupOrder] IN { 1, 4, 7 }, 0,
    Table1[GroupOrder] IN { 2, 5, 8 },
    VAR PreviousGroupOrder_ = Table1[GroupOrder] - 1
    RETURN
        CALCULATE (
            DISTINCT ( Table1[Value 1] ),
            Table1[GroupOrder] = PreviousGroupOrder_,
            ALLEXCEPT ( Table1, Table1[Date] )
        ),
    Table1[GroupOrder] IN { 3, 6, 9 },
    VAR PreviousGroupOrder2_ = Table1[GroupOrder] - 2
    RETURN
        CALCULATE (
            DISTINCT ( Table1[Value 1] ),
            Table1[GroupOrder] = PreviousGroupOrder2_,
            ALLEXCEPT ( Table1, Table1[Date] )
        )
)
Destrogiro's avatar
Destrogiro
Regular Visitor
6 years ago

Here is an example of what I need:

 

Date       GroupOrder    Value 1               Value 2

---------------------------------------------------------------------------------------------------------------------

20121231   1             322762272703.0400     0.0000
20121231   2             504993049586.4000     322762272703.0400
20121231   3             117421034783.7100     322762272703.0400
20121231   4             725451720271.6600     0.0000
20121231   5             1527350829053.5900    725451720271.6600
20121231   6             90925867161.1700      725451720271.6600
20121231   7             405811.0000           0.0000
20121231   8             105.0000              405811.0000
20121231   9             27.0000               405811.0000

 

When GroupOrder is 1,4,7 Value 2 should be 0

When GroupOrder is (2,5,8) Value 2 should have EARLIER(Value 1,1)

When GroupOrder is (3,6,9) Value 2 should have EARLIER(Value 1,2)

 

I was able to do it in SQL Server using LAG function. I don't know if it helps, but here is the SQL code:

 

SELECT DataReferencia, OrdemGrupo, GrupoInformacao, TipoInformacao, Valor AS ValorAtual,
CASE WHEN OrdemGrupo IN (2,5,8) THEN LAG(Valor,1,0) OVER (ORDER BY DataReferencia, OrdemGrupo, GrupoInformacao, TipoInformacao)
WHEN OrdemGrupo IN (3,6,9) THEN LAG(Valor,2,0) OVER (ORDER BY DataReferencia, OrdemGrupo, GrupoInformacao, TipoInformacao)
ELSE 0
END AS ValorTotal
FROM TCBLBI_Peso_Empresas_Tradadas
WHERE DataReferencia = 20121231

 

I hope it helps.

AlB's avatar
AlB
Community Champion
6 years ago

Hi Destrogiro 

EARLIER works in a completely different way from what you seem to be assuming. It gives you access to the outer row context, not to the previous row.  Try this for your calculated column, where I'm assuming you need this done by date:

 

Value2 =
SWITCH (
    TRUE (),
    Table1[GroupOrder] IN { 1, 4, 7 }, 0,
    Table1[GroupOrder] IN { 2, 5, 8 }, CALCULATE (
        DISTINCT ( Table1[Value 1] ),
        Table1[GroupOrder]
            = ( EARLIER ( Table1[GroupOrder] ) - 1 ),
        ALLEXCEPT ( Table1, Table1[Date] )
    ),
    Table1[GroupOrder] IN { 3, 6, 9 }, CALCULATE (
        DISTINCT ( Table1[Value 1] ),
        Table1[GroupOrder]
            = ( EARLIER ( Table1[GroupOrder] ) - 2 ),
        ALLEXCEPT ( Table1, Table1[Date] )
    )
)

 

   

 

  • AlB's avatar
    AlB
    Community Champion
    6 years ago

    Since the introduction of VAR, there's no actual need for EARLIER any longer.  So you might want to do it in a different way, perhaps easier to follow conceptually, and forget about EARLIER altogether (which is actually recommended nowadays):

    Value2 =
SWITCH (
    TRUE (),
    Table1[GroupOrder] IN { 1, 4, 7 }, 0,
    Table1[GroupOrder] IN { 2, 5, 8 },
    VAR PreviousGroupOrder_ = Table1[GroupOrder] - 1
    RETURN
        CALCULATE (
            DISTINCT ( Table1[Value 1] ),
            Table1[GroupOrder] = PreviousGroupOrder_,
            ALLEXCEPT ( Table1, Table1[Date] )
        ),
    Table1[GroupOrder] IN { 3, 6, 9 },
    VAR PreviousGroupOrder2_ = Table1[GroupOrder] - 2
    RETURN
        CALCULATE (
            DISTINCT ( Table1[Value 1] ),
            Table1[GroupOrder] = PreviousGroupOrder2_,
            ALLEXCEPT ( Table1, Table1[Date] )
        )
)
    • Destrogiro's avatar
      Destrogiro
      Regular Visitor
      6 years ago

      Thank you very much, AlB !

      It solved my problem!