Forum Discussion
Duplicate values on time span
I think this is what you need:
Find the names of the customers that have 2 different visit dates not more than 14 days apart.
Let's say your table that stores visits is V, you've got CustomerID and VisitDate in there. Then you also have a dimension table with your customers C where you store unique CustomerID's. C joins to T in a 1:many fashion on CustomerID. Then you could add a column [2 Visits Within 14 Days] to C:
[2 Visits Within 14 Days] = -- calculated column without the use of context transition
var __custId = C[CustomerID]
var __visitDates =
SUMMARIZE(
FILTER (
V,
V[CustomerId] = __custId
),
V[VisitDate]
)
var __2VisitsExist =
NOT ISEMPTY(
FILTER(
CROSSJOIN(
SELECTCOLUMNS (
__visitDates,
"FirstVD", V[VisitDate]
),
SELECTCOLUMNS(
__visitDates,
"SecondVD", V[VisitDate]
)
),
[SecondVD] - [FirstVD] < 14
&& [SecondVD] > [FirstVD]
)
)
return
__2VisitsExistBest
Darek
What does it mean "more than 1 time in 14 days"? Which 14 days? Where is the beginning and where is the end of the 14 days?
Best
Darek
It should be a cycle that checks every 14 days from the first date. That is, from 01.06 to 14.06, then from 02.06 to 15.06, and so on. I need a list of customers who visited cafe more than once in 14 days at any time.
Anonymous maybe you have some ideas? please
I think this is what you need:
Find the names of the customers that have 2 different visit dates not more than 14 days apart.
Let's say your table that stores visits is V, you've got CustomerID and VisitDate in there. Then you also have a dimension table with your customers C where you store unique CustomerID's. C joins to T in a 1:many fashion on CustomerID. Then you could add a column [2 Visits Within 14 Days] to C:
[2 Visits Within 14 Days] = -- calculated column without the use of context transition
var __custId = C[CustomerID]
var __visitDates =
SUMMARIZE(
FILTER (
V,
V[CustomerId] = __custId
),
V[VisitDate]
)
var __2VisitsExist =
NOT ISEMPTY(
FILTER(
CROSSJOIN(
SELECTCOLUMNS (
__visitDates,
"FirstVD", V[VisitDate]
),
SELECTCOLUMNS(
__visitDates,
"SecondVD", V[VisitDate]
)
),
[SecondVD] - [FirstVD] < 14
&& [SecondVD] > [FirstVD]
)
)
return
__2VisitsExistBest
Darek
Thank you very much for the answer. But the fact is that there can be more than two visits in 14 days and even several in one day, that is, the dates will be repeated.
