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JCuoco's avatar
JCuoco
Regular Visitor
4 years ago
Solved

Distinct Count one column with Contained Strings from another

Team,

I would like to do a distinct count on a column (Total Encounters) but only count the encounters that also have the value of "No Show" in a separate column 

Thanks,

James 

  • Hi JCuoco 

     

    You need to use Calculation with filter:

     

    If you want to filter the table to show the rows which have "No Show" in a seperate column:

    Measure = 
    Calculate(DISTINCTCOUNT(table[Total Encounters]),Filter(table,table[separate column]="No Show"))

    If "No Show" is part of the values of data in seperate column, use ValtteriN solution.

     

    If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
    Appreciate your Kudos!!
    LinkedIn: 
    www.linkedin.com/in/vahid-dm/

     

     

3 Replies

  • ValtteriN's avatar
    ValtteriN
    Community Champion

    Hi,

    Here is one way to do this:

     


    Dax:

    Apples =

    calculate(COUNT(Applecount[AppleCount]),ALL(Applecount)) //Calculate all fruits
    -
    CALCULATE(DISTINCTCOUNT(Applecount[AppleCount]),
    iserror(SEARCH("Apple",Applecount[AppleCount])),ALL(Applecount[AppleCount])) //calculate NOT apples


    End result:

     

    I hope this helps and if it does consider accepting this as a solution and giving the post a thumbs up!

  • Hi JCuoco 

     

    You need to use Calculation with filter:

     

    If you want to filter the table to show the rows which have "No Show" in a seperate column:

    Measure = 
    Calculate(DISTINCTCOUNT(table[Total Encounters]),Filter(table,table[separate column]="No Show"))

    If "No Show" is part of the values of data in seperate column, use ValtteriN solution.

     

    If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
    Appreciate your Kudos!!
    LinkedIn: 
    www.linkedin.com/in/vahid-dm/

     

     

    • JCuoco's avatar
      JCuoco
      Regular Visitor

      VahidDM thank you! This is absolutely perfect! love it! i did the "LONG" way last night and got the same number, so i know it is correct! THANK YOU