Forum Discussion
Dax filter syntax
Hello all
In DAX , how can i create a Measure that filter all values by a specific date for each value
for example :
I have a table with 3 columns : customer_id (PK) , country , register_date ( all data for all countries is from 1/1/2018 )
how can i create a parameter that filters the customer_id by a diffrent and specific date for each a country ?
show only customer_id from Spain that the register_date is >= 2/14/2018
And
show only customer_id from Canada that the register_date is >= 9/24/2018
And
show only customer_id from France that the register_date is >= 7/30/2019
Hello Anonymous,
You may try this measure:
Customer Count = VAR _Spain = DATE ( 2018, 2, 14 ) VAR _Canada = DATE ( 2018, 9, 24 ) VAR _France = DATE ( 2019, 7, 30 ) RETURN CALCULATE ( COUNT ( dtTable[CustomerID] ), FILTER ( dtTable, dtTable[Country] = "Spain" && dtTable[RegisterDate] >= _Spain ) ) + CALCULATE ( COUNT ( dtTable[CustomerID] ), FILTER ( dtTable, dtTable[Country] = "Canada" && dtTable[RegisterDate] >= _Canada ) ) + CALCULATE ( COUNT ( dtTable[CustomerID] ), FILTER ( dtTable, dtTable[Country] = "France" && dtTable[RegisterDate] >= _France ) )Then in the visual, you can add this as Filter = is not blank:
Cheers!
Vivek
If it helps, please mark it as a solution
Kudos would be a cherry on the top 🙂
https://www.vivran.in/
Connect on LinkedIn
2 Replies
- vivran22Community Champion
Hello Anonymous,
You may try this measure:
Customer Count = VAR _Spain = DATE ( 2018, 2, 14 ) VAR _Canada = DATE ( 2018, 9, 24 ) VAR _France = DATE ( 2019, 7, 30 ) RETURN CALCULATE ( COUNT ( dtTable[CustomerID] ), FILTER ( dtTable, dtTable[Country] = "Spain" && dtTable[RegisterDate] >= _Spain ) ) + CALCULATE ( COUNT ( dtTable[CustomerID] ), FILTER ( dtTable, dtTable[Country] = "Canada" && dtTable[RegisterDate] >= _Canada ) ) + CALCULATE ( COUNT ( dtTable[CustomerID] ), FILTER ( dtTable, dtTable[Country] = "France" && dtTable[RegisterDate] >= _France ) )Then in the visual, you can add this as Filter = is not blank:
Cheers!
Vivek
If it helps, please mark it as a solution
Kudos would be a cherry on the top 🙂
https://www.vivran.in/
Connect on LinkedIn- AnonymousNot applicable
Thank you very much vivran22 ! it helped a lot !