Forum Discussion
Count differents values with condition
Hi, I need a help to create a colunm in DAX.
The colunm "How many different hour" need to count how many different hours I have per "Type", for example:
Type A have 2 different hours (20:20:53 and 22:15:41) so the colunm "How many different hour" bring me 2.
Type B have 3 different hours (19:45:22, 08:12:00 and 12:34:56) so the colunm "How many different hour" bring me 3.
| ROW | Hour | Type | How many different hour |
| 1 | 20:20:53 | A | 2 |
| 2 | 20:20:53 | A | 2 |
| 3 | 20:20:53 | A | 2 |
| 4 | 22:15:41 | A | 2 |
| 5 | 22:15:41 | A | 2 |
| 6 | 22:15:41 | A | 2 |
| 7 | 22:15:41 | A | 2 |
| 8 | 22:15:41 | A | 2 |
| 9 | 22:15:41 | A | 2 |
| 10 | 19:45:22 | B | 3 |
| 11 | 19:45:22 | B | 3 |
| 12 | 08:12:00 | B | 3 |
| 13 | 08:12:00 | B | 3 |
| 14 | 08:12:00 | B | 3 |
| 15 | 12:34:56 | B | 3 |
| 16 | 12:34:56 | B | 3 |
| 17 | 12:34:56 | B | 3 |
Anybody can help me?
Thanks a lot.
- Anonymous3 years ago
Hi Anonymous ,
Here are the steps you can follow:
1. Create calculated column.
Flag = var _table1= SUMMARIZE('Table','Table'[Type],'Table'[Hour]) return COUNTX( FILTER(_table1, [Type]=EARLIER('Table'[Type])),[Hour])2. Result:
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
4 Replies
- AnonymousNot applicable
Not sure if this is the most efficient solution but try this as calculated column,
CalculatedColumn = var _Value = 'Table'[Type] var _Table = FILTER( 'Table', 'Table'[Type] = _Value ) var _Result = CALCULATE( DISTINCTCOUNT('Table'[Hour]), _Table ) return _Result- AnonymousNot applicable
Hello Anonymous
Doesn't work, appears this message: The expression refers to multiple columns. Multiple columns cannot be converted to a scalar value.
- AnonymousNot applicable
Hi Anonymous ,
Here are the steps you can follow:
1. Create calculated column.
Flag = var _table1= SUMMARIZE('Table','Table'[Type],'Table'[Hour]) return COUNTX( FILTER(_table1, [Type]=EARLIER('Table'[Type])),[Hour])2. Result:
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
- AnonymousNot applicable
Anonymous
Thanks a lot.