Forum Discussion

Sudhakar510's avatar
Sudhakar510
Helper I
3 years ago
Solved

Count and Rank Please

Hi Experts,

 

I am looking Count and Rank based on Single Criteria and also combination of 2 Criteria's.


Please see below Table A and Table B.  I am looking to achieve Result and Rank for Table A and Table B Please.

 

Table A I would like to acheive Result and Rank Please based on Values Column

 

Table B, I want to acheive Result and Rank based on Value and ID please

 

Please any Help?

Help
  • Anonymous's avatar
    Anonymous
    3 years ago

    hello Sudhakar510 
    i created a sample data

     

    the uncessary column is just an added column so the allexcept later on works, because i would assume you have more than those 2 columns 

    for table A with only values,use :

     

    Count of Items alone = CALCULATE(COUNT(Help[Value]),ALLEXCEPT(Help,Help[Value]))

     

    and for ranking

     

    table 1 rank = 
VAR __currentvalue = MAX(Help[Value])
VAR __tmpTable = ALL(Help)
VAR __tmpTable1 = SUMMARIZE(__tmpTable,Help[Value],"__Count",[Count of Items alone])
VAR __tmpTable2 = ADDCOLUMNS(__tmpTable1,"__Rank",RANKX(__tmpTable1,[__Count],,DESC,Dense))
RETURN MAXX(FILTER(__tmpTable2,Help[Value]=__currentvalue),[__Rank])

     


    now for table B:

     

    count of item per id = CALCULATE(COUNT(Help[Value]),ALLEXCEPT(Help,Help[ID],Help[Value]))

     

     

    but if you only have those 2 columns , id and value, use

     

    count of item per id = CALCULATE(COUNT(Help[Value]))

     

     

    for ranking:

     

    table 2 rank = 
VAR __currentid = MAX(Help[ID])
VAR __currentvalue = MAX(Help[Value])
VAR __tmpTable = ALL(Help)
VAR __tmpTable1 = SUMMARIZE(__tmpTable,Help[Value],Help[ID],"__Count",[count of item per id])
VAR __tmpTable2 = ADDCOLUMNS(__tmpTable1,"__Rank",RANKX(__tmpTable1,[__Count],,DESC,Dense))
RETURN MAXX(FILTER(__tmpTable2,AND(Help[Value]=__currentvalue,Help[ID] = __currentid)),[__Rank])

     

     

     

    if i solved you problem, a kudos is well appreciated as well as mark it as solved

     

     

3 Replies

  • Anonymous's avatar
    Anonymous
    Not applicable
    3 years ago

    hello Sudhakar510 
    i created a sample data

     

    the uncessary column is just an added column so the allexcept later on works, because i would assume you have more than those 2 columns 

    for table A with only values,use :

     

    Count of Items alone = CALCULATE(COUNT(Help[Value]),ALLEXCEPT(Help,Help[Value]))

     

    and for ranking

     

    table 1 rank = 
VAR __currentvalue = MAX(Help[Value])
VAR __tmpTable = ALL(Help)
VAR __tmpTable1 = SUMMARIZE(__tmpTable,Help[Value],"__Count",[Count of Items alone])
VAR __tmpTable2 = ADDCOLUMNS(__tmpTable1,"__Rank",RANKX(__tmpTable1,[__Count],,DESC,Dense))
RETURN MAXX(FILTER(__tmpTable2,Help[Value]=__currentvalue),[__Rank])

     


    now for table B:

     

    count of item per id = CALCULATE(COUNT(Help[Value]),ALLEXCEPT(Help,Help[ID],Help[Value]))

     

     

    but if you only have those 2 columns , id and value, use

     

    count of item per id = CALCULATE(COUNT(Help[Value]))

     

     

    for ranking:

     

    table 2 rank = 
VAR __currentid = MAX(Help[ID])
VAR __currentvalue = MAX(Help[Value])
VAR __tmpTable = ALL(Help)
VAR __tmpTable1 = SUMMARIZE(__tmpTable,Help[Value],Help[ID],"__Count",[count of item per id])
VAR __tmpTable2 = ADDCOLUMNS(__tmpTable1,"__Rank",RANKX(__tmpTable1,[__Count],,DESC,Dense))
RETURN MAXX(FILTER(__tmpTable2,AND(Help[Value]=__currentvalue,Help[ID] = __currentid)),[__Rank])

     

     

     

    if i solved you problem, a kudos is well appreciated as well as mark it as solved

     

     

  • Sudhakar510's avatar
    Sudhakar510
    Helper I
    3 years ago

    Thank you very much Anonymous , I will give a try with your measure and will update you as soon as possible. My network is super slow today but I am on it and will let you know soom as soon as ETL process finishes.