Forum Discussion

Gaurav_Lakhotia's avatar
Gaurav_Lakhotia
Helper III
5 years ago
Solved

Calculated Column for Latest Training Date

Hi All,

 

I need help in calculating the calculated column for latest date.

 

Scenario is, There is a TrainingTracker table which has Date column (i.e. Training Date).

I need to find out the date after 28 days of the Training Date. (For Example: If Training Date is 1st Sept 2020 than Latest Date will be 29th Sept 2020 i.e 1 Sept 2020 + 28 Days )

In case a second training was conducted within 28 days period of training for same Customer, the period end date will be a 28 days after second training. For Example: First Training Date is 1st Sept 2020 and within 28 days of First Training we've another Training on 15th Sept 2020, than the latest date will be 13 Oct 2020 i.e. 15th Sept + 28 Days, for both training.

 

Here is the file with sample data,

 Sample File 

 

Please help me out.

Thanks.

  • amitchandak's avatar
    amitchandak
    5 years ago

    Gaurav_Lakhotia , From what I got.

    You can have new column which tell diff from last training and you can use that

    new column =
    Datediff( maxx(filter(table ,[Customers Name] = earlier([Customers Name]) && [TrainingDate] <earlier([TrainingDate])),[TrainingDate]),[TrainingDate],day)

  • Hi amitchandak ,

     

    The DAX you've shared is calculating by taking very first Customer Training date as a base.

     

    We want it to consider every corresponding training date of each row to search within 28 days after training.

     

    Thanks

6 Replies

  • Greg_Deckler's avatar
    Greg_Deckler
    Community Champion

    Gaurav_Lakhotia I will look at PBIX but could you just use:

     

    New Column = [Training Date] + 28
    
    New Column 1 = IF([Second Training Date] < [New Column],[Second Training Date]+28,<something else>)

     

    • Gaurav_Lakhotia's avatar
      Gaurav_Lakhotia
      Helper III

      Hi Greg_Deckler ,

       

      We've Customer Name column. We've to lookup training dates customer wise. Here is sample data, look for first 2 entries of Sweet House Day Spa. We've 6 May 2020 and 16 May 2020.

       

      TrainingDate   Trainer'sName           Trainer'sType                                                         Customer's Name

      02-09-2020Jessica   Building a Strong Front Desk TeamSweet House Day Spa - Houston
      04-09-2020BrittanyBuilding a Strong Front Desk Team101 Skin Lab 
      06-09-2020BrittanyInventory Control / Product ManagementA New Leaf Flowers, Gifts, & More
      06-05-2020BrittanyAdvanced Modality TreatmentsSweet House Day Spa
      18-06-2020JenniferAdvanced Modality TreatmentsAidan James Salon
      26-06-2020WendyAdvanced Modality Treatments101 Market
      16-06-2020JessicaBuilding a Strong Front Desk TeamSweet House Day Spa
      07-09-2020BeckyBuilding a Strong Front Desk Team502 Flair
      23-05-2020BrittanyAdvanced Modality TreatmentsSweet House Day Spa
      • amitchandak's avatar
        amitchandak
        Super User

        Gaurav_Lakhotia , From what I got.

        You can have new column which tell diff from last training and you can use that

        new column =
        Datediff( maxx(filter(table ,[Customers Name] = earlier([Customers Name]) && [TrainingDate] <earlier([TrainingDate])),[TrainingDate]),[TrainingDate],day)