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CBXS's avatar
CBXS
Frequent Visitor
3 years ago
Solved

Calculated column based on multiple conditions using DAX

Hello.

I could use some assistance regarding a DAX algorithm, since I'm inexperienced in algorithms of this complexity.

I have about 15k rows with data similar to the table shown below.

 

I wish to construct the Decision column shown below based on each week and each person and the following conditions:

- Decision should be =1 the first two days for each person and for each week (assuming the person has different values for Day_in_week_for_event (see rows with Ken).

- If the same person has an event the same day, Decision should prioritize classification A (see rows with Bob)

- If a person has 1 or more classification A in the same week, the first two A occurences in the week must be Decision =1 (see rows with Jenny).

- Decision is 0 if it isn't 1

 

PersonWeeknumberDay_in_week_for_eventClassificationDecision
Bob11B0
Bob11A1
Jenny21B1
Jenny22B1
Jenny23A1
Jenny24A1
Jenny25A0
Ken22A1
Ken24B1
Ken25B0
Erick32B1

 

Any help will be much appreciated.

Let me know if you have any questions.

  • Hi, CBXS 

     

    First, you need to add an index column to Power Query.

     

    Column = 
    Var _N1=CALCULATE(COUNT('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Classification],'Table'[Weeknumber],'Table'[Day_in_week]))
    Var _N2=CALCULATE(MIN('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Classification],'Table'[Weeknumber],'Table'[Day_in_week]))
    Var _N3=CALCULATE(COUNT('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Weeknumber],'Table'[Day_in_week]))
    Var _Rank=RANKX(FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])),[Day_in_week],,ASC)
    Return
    IF(_N1>1&&[Index]=_N2,1,IF(_N3>1&&[Classification]="A",1,IF(_Rank<=2&&_N3=1,1,BLANK())))
    One week more A = 
     Var _RankA=IF([Classification]="A",RANKX(FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])&&[Classification]="A"),[Day_in_week],,ASC),BLANK())
    Return
    IF(_RankA<=2&&_RankA<>BLANK()&&[Column]=BLANK(),1,BLANK())
    Decision = SWITCH(TRUE(),
    [Column]=1,1,
    [One week more A]=1,1,
    0)

     

    Is this the result you expect?

     

    Best Regards,

    Community Support Team _Charlotte

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

     

5 Replies

  • v-zhangti's avatar
    v-zhangti
    Community Support

    Hi, CBXS 

     

    You can try the following methods.

    One week first two days = 
    Var _Rank=RANKX(FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])),[Day_in_week_for_event],,ASC)
    Return
    IF(_Rank<=2,1,0)
    One day more events = 
     Var _Countevent=CALCULATE(COUNT('Table'[Day_in_week_for_event]),FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Day_in_week_for_event]=EARLIER([Day_in_week_for_event])&&[Weeknumber]=EARLIER('Table'[Weeknumber])))
    Return
    IF(_Countevent>1&&[Classification]="A",1,IF(_Countevent=1,[One week first two days],0))
    Decision = 
    Var _CountA=CALCULATE(COUNT('Table'[Classification]),FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])&&[Classification]="A"))
    Var _RankA=IF([Classification]<>"A",BLANK(),RANKX(FILTER('Table',[Classification]="A"&&[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])),[Day_in_week_for_event],,ASC))
    return
    IF(_CountA>=1&&_RankA<=2&&_RankA<>BLANK(),1,[One day more events])

    Is this the result you expect?

     

    Best Regards,

    Community Support Team _Charlotte

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

    • CBXS's avatar
      CBXS
      Frequent Visitor

      Almost perfect!

       

      It doesn't look like the "One day two events" takes the weeknumber into account, as the Person= Erick row should be a 0 in the "One day two events" column, since it is the only row with weeknumber=3.

       

      Additionally, i forgot to mention another condition. If there are multiple events for a person on the same day in the same week, the Decision should be 1 in only one of those rows. Your code does this when the two events have different classification, but not if the classification is the same. It doesn't matter which row that gets Decision = 1.

       

      See the desired result in the last two rows with Person = Erick

      PersonWeeknumberDay_in_weekClassificationDecision
      Bob11B0
      Bob11A1
      Jenny21B1
      Jenny22B1
      Jenny23A1
      Jenny24A1
      Jenny25A0
      Ken22A1
      Ken24B1
      Ken25B0
      Erick32B1
      Erick32B0

       

      Thank you so much for helping me with my problem!

      • v-zhangti's avatar
        v-zhangti
        Community Support

        Hi, CBXS 

         

        First, you need to add an index column to Power Query.

         

        Column = 
        Var _N1=CALCULATE(COUNT('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Classification],'Table'[Weeknumber],'Table'[Day_in_week]))
        Var _N2=CALCULATE(MIN('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Classification],'Table'[Weeknumber],'Table'[Day_in_week]))
        Var _N3=CALCULATE(COUNT('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Weeknumber],'Table'[Day_in_week]))
        Var _Rank=RANKX(FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])),[Day_in_week],,ASC)
        Return
        IF(_N1>1&&[Index]=_N2,1,IF(_N3>1&&[Classification]="A",1,IF(_Rank<=2&&_N3=1,1,BLANK())))
        One week more A = 
         Var _RankA=IF([Classification]="A",RANKX(FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])&&[Classification]="A"),[Day_in_week],,ASC),BLANK())
        Return
        IF(_RankA<=2&&_RankA<>BLANK()&&[Column]=BLANK(),1,BLANK())
        Decision = SWITCH(TRUE(),
        [Column]=1,1,
        [One week more A]=1,1,
        0)

         

        Is this the result you expect?

         

        Best Regards,

        Community Support Team _Charlotte

        If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.