Forum Discussion
Average per row based on slicer
Hi all,
I have created a table and would like to create a measure that will average the values per row for the 2 previous years.
In the below table, the result for WEEK 41, for example, would be 487,003 (average of 2020 and 2021)
Thanks in advance
- Anonymous3 years ago
Hi danielcontente ,
Here are the steps you can follow:
1. Create measure.
Measure = var _today=YEAR(TODAY()) var _1year= SUMX(FILTER(ALL('Table'),'Table'[Year]=_today -1&&'Table'[Weeknumber]=MAX('Table'[Weeknumber])),[Value]) var _2year= SUMX(FILTER(ALL('Table'),'Table'[Year]=_today -2&&'Table'[Weeknumber]=MAX('Table'[Weeknumber])),[Value]) return DIVIDE( _1year+_2year,2)2. Result:
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
7 Replies
- AlB
Community Champion
1. Can you share a sample of the relevant tables in your model? Or, ideally, the pbix?
2. How are the "2 previous years" determined? Is it always 2020 and 2021 or dynamic?
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- danielcontente
Helper II
Hi, the table is in the first comment (there is a picture).
- danielcontente
Helper II
the previous two years are dynamic
- AlB
Community Champion
I cannot copy the data from a picture
Dynamic based on what? Why not 2022 and 2021?
Please accept the solution when done and consider giving a thumbs up if posts are helpful.
Contact me privately for support with any larger-scale BI needs, tutoring, etc.
- danielcontente
Helper II
Dynamic based on the current year.
- FreemanZ
Super User
try like:
Average = VAR _2020 = CALCULATE(SUM(TableName[Value]), YEAR(TableName[Date])=2020) VAR _2021 = CALCULATE(SUM(TableName[Value]), YEAR(TableName[Date])=2021) RETURN (_2020+_2021)/2 - AnonymousNot applicable
Hi danielcontente ,
Here are the steps you can follow:
1. Create measure.
Measure = var _today=YEAR(TODAY()) var _1year= SUMX(FILTER(ALL('Table'),'Table'[Year]=_today -1&&'Table'[Weeknumber]=MAX('Table'[Weeknumber])),[Value]) var _2year= SUMX(FILTER(ALL('Table'),'Table'[Year]=_today -2&&'Table'[Weeknumber]=MAX('Table'[Weeknumber])),[Value]) return DIVIDE( _1year+_2year,2)2. Result:
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly