Forum Discussion

Pan_Forex's avatar
Pan_Forex
Icon for Helper III rankHelper III
3 years ago
Solved

Average from 2 tables

Hi guys, I would like to count the average in each game depending on which players were in it. I have 2 tables connected by a one-to-many relationship. They look like this:   ID Player 1 A ...
  • v-zhangti's avatar
    v-zhangti
    3 years ago

    Hi, Pan_Forex 

     

    You can try the following methods.

    Column:

    Score = LOOKUPVALUE(Score[Score],Score[Player],[Player])

    Measure:

    Measure = CALCULATE(AVERAGE(Player[Score]),ALLEXCEPT(Player,Player[ID]))

    Measure 2 = 
VAR _table = CALCULATETABLE(VALUES('Player'[ID]),FILTER(ALL('Player'),'Player'[Player]=SELECTEDVALUE(Player[Player])))
RETURN
CALCULATE(AVERAGE(Player[Score]),FILTER(ALL(Player),[ID] in _table))

    Is this the result you expect?

     

    Best Regards,

    Community Support Team _Charlotte

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

     

Jihwan_Kim's avatar
Jihwan_Kim
Icon for Super User rankSuper User
3 years ago

Hi,

Thank you for your message.

May I ask what is the expected number that you want to see for each player?

Pan_Forex's avatar
Pan_Forex
Icon for Helper III rankHelper III
3 years ago

Sure, here we go: 

Player A- 5,77 

Player B- 5,77

Player C- 5,82

 

 

  • v-zhangti's avatar
    v-zhangti
    Icon for Community Support rankCommunity Support
    3 years ago

    Hi, Pan_Forex 

     

    You can try the following methods.

    Column:

    Score = LOOKUPVALUE(Score[Score],Score[Player],[Player])

    Measure:

    Measure = CALCULATE(AVERAGE(Player[Score]),ALLEXCEPT(Player,Player[ID]))

    Measure 2 = 
VAR _table = CALCULATETABLE(VALUES('Player'[ID]),FILTER(ALL('Player'),'Player'[Player]=SELECTEDVALUE(Player[Player])))
RETURN
CALCULATE(AVERAGE(Player[Score]),FILTER(ALL(Player),[ID] in _table))

    Is this the result you expect?

     

    Best Regards,

    Community Support Team _Charlotte

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.