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davidinternship's avatar
davidinternship
New Member
6 years ago
Solved

Average calculation in same column but for different values

Hello everyone,

I'm trying to calculate the average of some different values in the same column. And after that, using that result to divide another value in the same column, resulting a value in porcetage.

 

The example of the table and the equation are shown below:


For ID CODE 41:            X =[ 10 / (20+5/2) ] - 1
                                               |        |    |
TYPE-------------->               A       B   C -> media between B and C


I really appreciate for the help.

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  • Anonymous's avatar
    Anonymous
    6 years ago
    // Of course, your notation is incorrect.
// The formula should read:
//
// 		X = [2A / (B + C)] - 1
//
// In mathematics IT DOES MATTER where you put
// brackets. Note that such a calculation should
// be performed in Power Query, not in DAX.

[New Column] = // column, not a measure
var __code = T[ID Code]
var __a =
	MAXX(
		filter(
			T,
			T[ID Code] = __code
			&&
			T[Type] = "A"
		),
		T[Value]
	)
var __b =
	MAXX(
		filter(
			T,
			T[ID Code] = __code
			&&
			T[Type] = "B"
		),
		T[Value]
	)
var __c =
	MAXX(
		filter(
			T,
			T[ID Code] = __code
			&&
			T[Type] = "C"
		),
		T[Value]
	)
return
	DIVIDE(
		2 * __a,
		__b + __c
	) - 1

// If you want a calculated table,
// you can do this:

[Calc Table] =
ADDCOLUMNS(
	VALUES( T[ID Code] ),
	"X",
		var __code = T[ID Code]
		var __a =
			MAXX(
				filter(
					T,
					T[ID Code] = __code
					&&
					T[Type] = "A"
				),
				T[Value]
			)
		var __b =
			MAXX(
				filter(
					T,
					T[ID Code] = __code
					&&
					T[Type] = "B"
				),
				T[Value]
			)
		var __c =
			MAXX(
				filter(
					T,
					T[ID Code] = __code
					&&
					T[Type] = "C"
				),
				T[Value]
			)
		return
			DIVIDE(
				2 * __a,
				__b + __c
			) - 1
)

    Best

    D

3 Replies

  • Greg_Deckler's avatar
    Greg_Deckler
    Community Champion
    6 years ago

    Not sure I follow this, but if you want the average of each ID CODE, for example, you could do this:

     

    New Column = AVERAGEX(FILTER('Table',[ID CODE] = EARLIER([ID CODE])),[Value])

  • Anonymous's avatar
    Anonymous
    Not applicable
    6 years ago
    // Of course, your notation is incorrect.
// The formula should read:
//
// 		X = [2A / (B + C)] - 1
//
// In mathematics IT DOES MATTER where you put
// brackets. Note that such a calculation should
// be performed in Power Query, not in DAX.

[New Column] = // column, not a measure
var __code = T[ID Code]
var __a =
	MAXX(
		filter(
			T,
			T[ID Code] = __code
			&&
			T[Type] = "A"
		),
		T[Value]
	)
var __b =
	MAXX(
		filter(
			T,
			T[ID Code] = __code
			&&
			T[Type] = "B"
		),
		T[Value]
	)
var __c =
	MAXX(
		filter(
			T,
			T[ID Code] = __code
			&&
			T[Type] = "C"
		),
		T[Value]
	)
return
	DIVIDE(
		2 * __a,
		__b + __c
	) - 1

// If you want a calculated table,
// you can do this:

[Calc Table] =
ADDCOLUMNS(
	VALUES( T[ID Code] ),
	"X",
		var __code = T[ID Code]
		var __a =
			MAXX(
				filter(
					T,
					T[ID Code] = __code
					&&
					T[Type] = "A"
				),
				T[Value]
			)
		var __b =
			MAXX(
				filter(
					T,
					T[ID Code] = __code
					&&
					T[Type] = "B"
				),
				T[Value]
			)
		var __c =
			MAXX(
				filter(
					T,
					T[ID Code] = __code
					&&
					T[Type] = "C"
				),
				T[Value]
			)
		return
			DIVIDE(
				2 * __a,
				__b + __c
			) - 1
)

    Best

    D

    • davidinternship's avatar
      davidinternship
      New Member
      6 years ago

      Thank you for the answer. It helpde me a lot.

      I just needed to change little things to adapt on my need, but your answer was fundamental. 

      Best wishes!